If f is the frequency when mass m is attached to a spring of spring constant k, then new frequency for this arrangement, is

Options

A. `f//2`
B. `sqrt(2)f`
C. `f//sqrt(2)`
D. `2 sqrt(2)f`

Answer

B

Explanation

The frequency of oscillation of spring mass system is given by
`f = (1)/(2pi)sqrt((k)/(m))`
For the given arrangement, `k'=k_(1)+k_(2)=k+k=2k`
Hence, frequency of oscillation is
`f'=(1)/(2pi)sqrt((k')/(m))=(1)/(2pi)sqrt((2k)/(m))=sqrt(2)f`