Home
Class 12
PHYSICS
Two simple harmonic motions of angular f...

Two simple harmonic motions of angular frequency `100 rad s^(-1)` and `1000 rad s^(-1)` have the same displacement amplitude. The ratio of their maximum accelerations is

A

`1 : 10`

B

`1 : 10^(2)`

C

`1 : 10^(3)`

D

`1 : 10^(4)`

Text Solution

Verified by Experts

The correct Answer is:
B

Acceleration of simple harmonic motion is `a_(max)=-omega^(2)A`
or `((a_(max))_(1))/((a_(max))_(2))=(omega_(1)^(2))/(omega_(2)^(2))" "("as A remains same")`
or `((a_(max))_(1))/((a_(max))_(2))=((100)^(2))/((1000)^(2))=((1)/(10))^(2)=1:10^(2)`
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise EXERCISE 2|49 Videos
  • MOCK TEST 5

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MCQs|42 Videos
  • PRACTICE SET 01

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise PAPER 1 (PHYSICS & CHEMISTRY)|50 Videos

Similar Questions

Explore conceptually related problems

Two simple harmonic motion of angular frequency 100and 1000 rads^(-1) have the same displacement amplitude The ratio of their maximum acceleration is

A body is executing simple harmonic motion with an angular frequency s rad/2 . The velocity of the body at 20 mm displacement, when the amplitude of motion is 60 mm , is

A ball hung from a vertical spring oscillates in simple harmonic motion with an angular frequency of 2.6 rad/s and an amplitude of 0.075m. What is the maximum acceleration of the ball?

The angular frequency is measured in rad s^(-1) . Its dimension in length are :

A simple harmonic motion of amplitude A has a time period T. The acceleration of the oscillator when its displacement is half the amplitude is

The ratio of maximum acceleration to maximum velocity in a simple harmonic motion is 10 s^(-1) At, t = 0 the displacement is 5 m. What is the maximum acceleration ? The initial phase is (pi)/(4)

A simple harmonic oscillator of angular frequency 2 "rad" s^(-1) is acted upon by an external force F = sint N . If the oscillator is at rest in its equilibrium position at t = 0 , its position at later times is proportional to :-

A body makes angular simple harmonic motion of amplitude pi//10rad and time period 0.05s . If the body is at a displacement theta = pi//10 rad at t = 0 , write the equation giving angular displacement as a function of time.

A particle executing simple harmonic motion with an amplitude A and angularr frequency omega . The ratio of maximum acceleration to the maximum velocity of the particle is

The angular velocity of a particle changes from 100 rad s^(-1) to 200 rad s^(-1) in 4s . Calculate the angular accelertion of the particle ?

MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-OSCILLATIONS-MHT CET CORNER
  1. A block rests on a horizontal table which is executing SHM in the hori...

    Text Solution

    |

  2. A particle executes a simple harmonic motion of time period T. Find th...

    Text Solution

    |

  3. Two simple harmonic motions of angular frequency 100 rad s^(-1) and 10...

    Text Solution

    |

  4. The average acceleration of a particle performing SHM over one complet...

    Text Solution

    |

  5. U is the PE of an oscillating particle and F is the force acting on it...

    Text Solution

    |

  6. If a simple pendulum oscillates with an amplitude of 50 mm and time pe...

    Text Solution

    |

  7. The periodic time of a particle doing simple harmonic motion is 4 seco...

    Text Solution

    |

  8. The graph between time period (T) and length (l) of a simple pendulum ...

    Text Solution

    |

  9. The potential energy of a simple harmonic oscillator when the particle...

    Text Solution

    |

  10. In SHM restoring force is F = -kx, where k is force constant, x is dis...

    Text Solution

    |

  11. The displacement equation of a simple harmonic oscillator is given by ...

    Text Solution

    |

  12. Two particles execute SHM of same amplitude and frequency on parallel ...

    Text Solution

    |

  13. A simple pendulum of length I and mass (bob) m is suspended vertically...

    Text Solution

    |

  14. SHM given by x= 6 sin omega t + 8 cos omega t . Its amplitude is

    Text Solution

    |

  15. A point mass m is suspended at the end of a massless wire of length l ...

    Text Solution

    |

  16. Two partical A and B execute simple harmonic motion according to the ...

    Text Solution

    |

  17. Displacement of a particle executing SHM s x= 10 ( cos pi t + sin pi t...

    Text Solution

    |

  18. Time period of a simple pendulum will be double, if we

    Text Solution

    |

  19. Two springs, of spring constants k(1) and K(2), have equal highest vel...

    Text Solution

    |

  20. The velocity of a particle performing simple harmonic motion, when it ...

    Text Solution

    |