If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity is

Options

A. 0.10 `ms^(-1)`
B. 0.15 `ms^(-1)`
C. 0.8 `ms^(-1)`
D. 0.26 `ms^(-1)`

Answer

B

Explanation

`V_(max) = a omega = a xx (2pi)/(T) = (50 xx 1^(-3)) xx (2 pi)/(2) = 0.15 ms^(-1)`