The maximum velocity and the maximum acceleration of a body moving in a simple harmonic oscillator are 2 m/s and` 4 m//s^(2)`. Then angular velocity will be

Options

A. 3 `rads^(-1)`
B. 0.5 `rads^(-1)`
C. 1 `rads^(-1)`
D. 2 `rads^(-1)`

Answer

D

Explanation

At extreme position, displacement of particle
executing SHM is maximum. Maximum velocity of particle
executing SHM is given by
`therefore" "v_(max) = omega A`
Maximum acceleration of particle executing SHM is given
by, `a =-omega^(2)A or a_(max)=|A|=omega^(2)A`
As `a_(max)=(Aomega)omega=v_(max).omega`
`therefore" "omega=(a_(max))/(v_(max))=(4)/(2)=2 rads^(-1)`