If the angle of shear is `30^(@)` for a cubical body and the change in length is 250 cm, then what must be the volume of this cubical body.

Options

A. `81.295 m^(3)`
B. `71.309 m^(3)`
C. `91.106 m^(3)`
D. `83.266 m^(3)`

Explanation

Given, angle of shear `= 30^(@)`
and change in length, `Delta L = 250 cm = 2.5 m`
`:.` Shear strain, `tan theta = (Delta L)/(L)`
` implies tan 30^(@) = (2.5)/(L)`
`L = (2.5)/(tan 30^(@)) = (2.5)/(0.577) = 4.332 m`
Volume, `V = L^(3)`
`= (4.332)^(3) = 81.295 m^(3)`