Find the change in volume of a lead block of volume 2 `m^(3)` Which is subjected to pressure of 20 atm. (Take, 1 atm `= 1.013 xx 10^(5) N//m^(2)` and bulk modulus `= 8 xx 10^(9) N//m^(2)`)

Options

A. `5.065 xx 10^(-4) m^(3)`
B. `2.326 xx 10^(-5) m^(3)`
C. `8.325 xx 10^(-6) m^(3)`
D. `4.203 xx 10^(-3) m^(3)`

Explanation

Given, volume `V = 2 m^(3)`
`P = 20 atm = 20 xx 1.013 xx 10^(5) N//m^(2)`
`P = 20.26 xx 10^(5) N//m^(2)`
`B = 8 xx 10^(9) N//m^(2)`
`dV = ?`
Bulk modulus (B) `= V (P)/(dV)`
`dV = (Vp)/(B) = (2 xx 20.26 xx 10^(5))/(8 xx 10^(9))`
`dV = 5.065 xx 10^(-4) m^(3)`