Calculate the work done in stretching a steel wire of Young's modulus of `2 xx 10^(11) Nm^(-2)`, mass of 40 kg, length of 200 cm and area of cross-section is `0.06 cm^(2)`~ slowly applied without the elastic limit being reached.

Options

A. 2.502 j
B. 1.103 j
C. 0.9 j
D. 0.128 j

Explanation

To calculate the work done in stretching a steel wire, we can use the formula for work done in stretching a wire, which is given by:

\[ W = \frac{1}{2} F \Delta L \]

Where:
- \( W \) is the work done,
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