The density of a metal at normal pressure is `rho`. Its density when it is subjected to an excess pressure p is `rho'` . If B is the bluk modulus of the metal, then find the ratio `rho'//rho`.

Options

A. `(1)/(1 - (p)/(B))`
B. `1 + (B)/(P)`
C. `(1)/(1 - (B)/(P))`
D. `1 + (P)/(B)`

Answer

a

Explanation

`rho = (m)/(V)` or `rho prop (1)/(V)`
`:. (rho')/(rho) = (V)/(v_(1)) = (V)/(V + dV)` `(B = - (P)/(dV//V))`
`= (V)/(V-(Vp)/(B)) = (1)/(1 - (P)/(B))`