If the volume of a block os aluminium is decreased be `1%` the pressure (stress) on is surface is increased by (Bulk moduals) of `Al=7.5xx10^(10)Nm^(-2))`

Options

A. `7.5 xx 10^(10) Nm^(-2)`
B. `7.5 xx 10^(8) Nm^(-2)`
C. `7.5 xx 10^(6) Nm^(-2)`
D. `7.5 xx 10^(4) Nm^(-2)`

Answer

b

Explanation

Given, `(Delta V)/(V) xx 100 = 1% = (1)/(100)`
Bulk modulus, `B = (P)/(Delta V //V) = (pV)/(Delta V)`
or `P = (B Delta V)/(V) = 7.5 xx 10^(10) xx (1)/(100)`
`= 7.5 xx 10^(8) Nm^(-2)`