A `0.1kg` mass is suspended from a wire of negligible mass. The length of the wire is 1m and its crosssectional are is `4.9xx10^-7m^2`. If the mass is pulled a little in the vertically downward direction and released, it performs simple harmonic motion of angular frequency `140 rad s^-1`. If the Young's modulus of the material of the wire is `nxx10^9 Nm^-2`, the value of n is

Options

A. 4
B. 2
C. 5
D. 5

Answer

a

Explanation

`omega = = sqrt((K)/(m)) = sqrt((YA)/(Im))`
`= sqrt(((n xx 10^(9))(4.9 xx 10^(-7)))/(1 xx 0.1))`
Given,`omega = 140 rad s^(-1)` in above equation, we get,