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Let a steel bar of length l, breadth b a...

Let a steel bar of length `l`, breadth b and depth d be laoded at the centre by a load W. Then the sag of bending of beam is (Y = young's modulus of material of steel)

A

`(W l^(2))/(2bd^(3) Y)`

B

`(W l^(3))/(4bd^(3) Y)`

C

`(W l^(2))/(2bd^(3) Y)`

D

`(W l^(3))/(4bd^(2) Y)`

Text Solution

Verified by Experts

The correct Answer is:
b
According t question , the quesiton, the sag of bending of beam is given by
`delta = (Wl^(3))/(48 YI)`
Where, W = load, l = length, Y = Young's modulus
I = moment of inertia, `= (bd^(3))/(12)`
so, `delta = (Wl^(3))/(48 Y bd^(3)) xx 12 = (Wl^(3))/(4Y bd^(3))`
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