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A string of length L and force constant ...

A string of length L and force constant k is stretched to obtain extension l. It is further stretched to obtain extension `l_(1)`. The work done in second streching is

A

`(1)/(2) KI_(1) (2I + I_(1))`

B

`(1)/(2) KI_(1)^(2)`

C

`(1)/(2) K (I^(2) + I_(1)^(2))`

D

`(1)/(2) (I_(1)^(2) - I^(2))`

Text Solution

Verified by Experts

The correct Answer is:
d

Work done in stretching a string to obtain in extension I is
`W_(1) = (1)/(2) Ki^(2)`
`:.` work done in second case `= W_(2) - W_(1) K (K_(1)^(2) - I^(2))`
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