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Work done in forming a liquid drop of ra...

Work done in forming a liquid drop of radius R is `W_(1)` and that of radius 3R is `W_(2)`. The ratio of work done is

A

`1:3`

B

`1:2`

C

`1:4`

D

`1:9`

Text Solution

Verified by Experts

The correct Answer is:
D

Surface energy is amount of work done.
`W = S xx 4pi R^(2)`
`rArr (W_(1))/(W_(2)) = (S xx 4pi R^(2))/(S xx 4pi (3R^(2))) = (1)/(9)`
`:. W_(1) : W_(2) = 1:9`
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