A vessel is filled with an ideal gas at a pressure of `10` atmospheres and temp `27^(0)C`. Half of the mass of the gas is removed from the vessel the temperature of the remaining gas is increased to `87^(0)C`. Then the pressure of the gas in the vessel will be

Options

A. 5 atm
B. 6 atm
C. 7 atm
D. 8 atm

Answer

B

Explanation

According to Ideal gas equation, pV=nRT
`(pV)/(T)=nR=(m)/(M)RrArr(m)/(M)R=(10xxv)/(300)`
`(m)/(2M)R=(pV)/(360)rArr(pV)/(360)=(1)/(2)(10V)/(300)`
The pressure of the gas `p=(3600)/(2xx300)=6` atm