KE per unit volume is E. The pressure exerted by the gas is given by

Options

A. `(E)/(3)`
B. `(2E)/(3)`
C. `(3E)/(2)`
D. `(E)/(2)`

Answer

B

Explanation

The pressure exerted by the gas , `=(1)/(3)rhomc^(-2)=(1)/(3)c^(-2)=(2)/(3)((1)/(2)mc^(-2))`
`(because(1)/(2)mc^(-2)=(E)/(V)="energy per unit volume",V=1)`
`p=(2)/(3)E`