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The wavelength of maximum energy release...

The wavelength of maximum energy released during an atomic axplosion was `2.93xx10^(-10)m`. Given that Wien's constant is `2.93xx10^(-3)m-K`, the maximum temperature attained must be of the order of

A

`5.86xx10^(7)K`

B

`10^(-13)`

C

`10^(-7)K`

D

`10^(7)K`

Text Solution

Verified by Experts

The correct Answer is:
D
Apply Wien 's displacement law,
`lambda_(m)T=2.93xx10^(-3)`
`T=(2.93xx10^(-3))/(lamda_(m))`
`=(2.93xx10^(-3))/(2.93xx10^(-10))=10^(7)K`
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