Define Snell's law of refraction. A ray of light is incident on a glass slab at angle of incidence of `60^(@)`. If the angle of refraction be `32.7^(@)`, calculate the refractive index of glass. (Given: sin`60^(@)=0.866` and `sin32.7^(@)=0.540)`.

Options

A. `sin^(-1)(0.5773)`
B. `sin^(-1)(0.638)`
C. `sin^(-1)(0.523)`
D. `sin^(-1)(0.4387)`

Answer

A

Explanation

Given, `anglei=60^(@),mu_(g)=1.5`
`mu_(g)=(sini)/(sinr)`
`therefore" "sinr=(sini)/(mu_(g))=(sin60^(@))/(1.5)`
`=(0.8660)/(1.5)=0.5773`
`therefore" "r=sin^(-1)(0.5773)`