The Brewster angle for the glass air interface is `54.74^(@)` if a ray of light going from air to glass strikes at an angle of incidence `45^(@)` then the angle of refraction is

Options

A. `60^(@)`
B. `30^(@)`
C. `25^(@)`
D. `54.74^(@)`

Answer

B

Explanation

Refractive index, `mu=tantheta=sqrt2`
Now according to Snell's law,
`sqrt2=(sin(54.74))/sinr`
`sinr=(0.816)/(sqrt2)=0.57`
`r=35^(@)=30^(@)`