Polarising angle for water is `53^(@)4'`. If light is incident at this angle on the surface of water and reflected, the angle of refraction is

Options

A. `30^(@)4'`
B. `36^(@)56'`
C. `37^(@)5'`
D. `29^(@)2'`

Answer

B

Explanation

`therefore` Acording to law of reflection,
Angle of incidence = Angle of reflection
`rArr" "i=r`
Since, the reflected and redracted rays are perpendicular to each other, when the ray is incident at polarising angle.
`therefore" "53^(@)4'+90^(@)+r'=180^(@)`
`therefore" "r'=90^(@)-53^(@)4'=36^(@)56'`
`rArr" "r'=36^(@)56'`