A ray of light is incident on a medium boundry at polarising angle such that its deviation is `24^(@)`, then angle of incidence is :

Options

A. `24^(@)`
B. `57^(@)`
C. `66^(@)`
D. `90^(@)`

Answer

B

Explanation

Here, `i_(p)=r+delta`

`i_(p)=r+24" "...(i)`
Moreover," "`i_(p)+r=90^(@)" "...(ii)`
From Eqs. (i) and (ii), we get
`i_(p)+(i_(p)-24)=90^(@)rArri_(p)=57^(@)`