Charge Q is given by the displacement `r=a hati+bhat j` in an electrif field `E=E_(1)hati+E_(2)hatj`. The work done is

Options

A. `Q((E_(1)a)+(E_(2)b))`
B. `Qsqrt((E_(1)a)^(2)+(E_(2)b)^(2))`
C. `Q(E_(1)+E_(2))sqrt(a^(2)+b^(2))`
D. `Q(sqrt(E_(1)^(2)+E_(2)^(2)))sqrt(a^(2)+b^(2))`

Answer

A

Explanation

Work done , `W=F.R = QE.r = Q(E_(1)hati+E_(2)hatj).(ahati+bhatj)`
`=QE_(1)q+QE_(2)b=Q(E_(1)a+E_(2)b)`