In the arrangement of capacitors shown in the figure, each capacitor is of `9muF`, then the equivalent capacitance between the point A and B is

Options

A. `9muF`
B. `18muF`
C. `4.5muF`
D. `15muF`

Answer

D

Explanation

The arrangement can be redrawn as shown in adjoining figure,

`therefore" "C_(13)=C_(1)+C_(3)=9+9=18muF`
`"and "C_(2-13)=(C_(2)xxC_(3))/(C_(2)+C_(13))`
`=(9muFxx18muF)/((9+18)muF)=6muF`
`therefore" "C=C_(2-13)+C_(4)=(6+9)muF=15muF`