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Two identical parallel plate capacitors are placed in series and connected to a constant voltage source of `V_0` volt. If one of the capacitors is completely immersed in a liquid with dielectric constant K, the potential difference between the plates of the other capacitor will change to -

A

`(K)/(K+1)V`

B

`(K+1)/(K)`

C

`(2K)/(K+1)`

D

`(K+1)/(2K)V`

Text Solution

Verified by Experts

The correct Answer is:
A

In series combination, charge is constant.
`therefore" "Vprop (1)/(C)`
`"Now, "(V_(2))/(V_(1))=(KC)/(C)=(K)/(1) rArr V_(2)=(V_(2))/(K)`
`"But "V_(1)+V_(2)=V or (V_(2))/(K)+V_(2)=V`
`rArr " "V_(2)=(K)/(K+1)V`
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