If power dissipated in the `9 Omega` resistor in the resistor shown is `36 W`, the potential difference across the `2 Omega` resistor is

Options

A. 8V
B. 10V
C. 2V
D. 4V

Answer

B

Explanation

Electric power, `P = i^(2)R`
`therefore " "` Current, `I = sqrt((P)/(R ))`
For resistance of 9 `Sigma`,
`i_(1)=sqrt((36)/(9))=sqrt(4)=2A`
`i_(2)=(i_(1)xxR)/(6)=(2xx9)/(6)=3A`
`i=i_(1)+i_(2)=2+3=5A`
`V_(2)=lR_(2)=5xx2=10V`