In the circuit given E = 6.0 volt, `R_(1) = 100Omega, R_(2) = R_(3)=50Omega` and `R_(4)=75Omega`. The equivalent resistance of the circuit, in ohms is

Options

A. 11.875
B. 26.31
C. 118.75
D. None of these

Answer

C

Explanation

`R_(2), R_(3)` and `R_(4)` are in parallel order, so their equivalent resistance
`(1)/(R')=(1)/(R_(2))+(1)/(R_(3))+(1)/(R_(4))=(1)/(50)+(1)/(50)+(1)/(75)`
`therefore " " R'=(75)/(4)Omega`
`R=R_(1)+R'=100+(75)/(4)=118.75 Omega`