Four resistances are connected in a circuit in the given figure. The electric cirrent flowing through `4 ohm` and `6 ohm` resistance is respectively

Options

A. 2A and 4A
B. 1A and 2A
C. 1A and 1A
D. 2A and 2A

Answer

D

Explanation

Resistance of `4 Omega` and `4 Omega` are in parallel, their equivalent resistance `= 2 Omega`
Similarly, equivalent resistance of `6 Omega` and `6Omega = 3 Omega`
Now `2 Omega` and `3 Omega` are in series, hence their total resistance
`R = 2+3=5 Omega`
From `V = iR rArr i = (V)/(R )=(20)/(5)=4 A`
This current will be equally divided in `4 Omega` and `6 Omega` resistance
So, current through `4 Omega` and `6 Omega` resistance is 2A respectively.