Five resistors are connected as shown in figure. Find the equivalent resistance between the points B and C.

Options

A. `(70)/(19)Omega`
B. `(19)/(70)Omega`
C. `(16)/(5)Omega`
D. `(15)/(8)Omega`

Answer

A

Explanation

Resistance in the branch ADC.
`R_(1)=3Omega+7Omega = 10 Omega`
Since, arms `ADC(10 Omega)` and `AC (10 Omega)` are in parallel their equivalent resistance, `R_(2)=(10xx10)/(10+10)Omega = 5 Omega`
Since, `R_(2)` is in series with `9 Omega` in arm AB, equivalent resistance between B and C,
i.e., `R_(BC)=(14xx5)/(14+5)=(70)/(19)Omega`