In the circuit given here, the points A,B and C are 70 V, zero, 10 V respectively . Then,

Options

A. the point d will be at a potential of 60 V
B. the point D will be at a potential of 20 V
C. currents in the paths AD, DB and DC are in the ratio of `1:2:3`
D. currents in the paths AD, DB and DC are in the ratio of `3:2:1`

Answer

D

Explanation

Applying Kirchhoff's law at point D, we get
`i_(1)=i_(2)+i_(3)`
`(V_(A)-V_(D))/(10)=(V_(D)-V_(B))/(20)+(V_(D)-V_(C ))/(30)`
`rArr " " 70-V_(D)=(V_(D))/(2)+(V_(D)-10)/(3)rArr V_(D)=40V`
`i_(1)=(70-40)/(10)=3A rArr i_(2)=(40-0)/(20)=2A`
and `i_(3)=(40-10)/(30)=1A`
So, the ratio will be 3 : 2 : 1.