In the following circuit `E_(1)=E_(2)=E_(3) 2V` and `R_(1)=R_(2)=AOmega`. The current passing through battery `E_(2)` between points A and B is

Options

A. Zero
B. 2A, B and A
C. 2A, A and B
D. None of these

Answer

C

Explanation

The given circuit can be redrawn

`E_(eq)=(E_(1)R_(2)+E_(2)R_(1))/(R_(1)+R_(2))=(2xx4+2xx4)/(4+4)=(16)/(8)=2`
and `R_(eq)=(4)/(2)=2 Omega`
Current, `i=(2+2)/(2)=2A` from A to B though.