In the electric circuit shown each cell has an emf of 2 V and internal resistance of `1Omega`. The external resistance is `2Omega` . The value of the current is (in A)

Options

A. 2
B. 1.25
C. 0.4
D. 1.2

Answer

D

Explanation

By Kirchhoff's law, `Sigma E = Sigma ir`
`E_(1)+E_(2)+E_(3)=i(r+R)`
`2+2+2=i(3+2)`
The value of the current
`rArr " " i=(6)/(5)=1.2 A`