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If the free electron density be n and re...

If the free electron density be n and relaxation time be `tau`, the electrical conductivity of a conductor may be expressed as

A

`("ne "tau)/(m_(e))`

B

`("ne"^(2)tau)/(m^(e))`

C

`("ne"^(2))/(tau m_(e))`

D

`(m_(e)e^(2) tau)/(n)`

Text Solution

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The correct Answer is:
B

Resistivity, `rho=(m_(e))/("ne"^(2)tau)`
Conductivity, `sigma =(1)/(rho)=("ne"^(2)tau)/(m_(e))`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-CURRENT ELECTRICITY-EXERCISE 2
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