A 2 V battery, a `990Omega` resistor and a potentiometer of 2 m length, all are connected in series of the resistance of potentiometer wire is `10Omega`, then the potential gradient of the potentiometer wire is

Options

A. `0.05 Vm^(-1)`
B. `0.5Vm^(-1)`
C. `0.01 Vm^(-1)`
D. `0.1 Vm^(-1)`

Answer

C

Explanation

Potential gradient `x=(e )/((R+R_(h)+r)).(R )/(L)`
`rArr " " x=(2)/((990+10))xx(10)/(2)=0.01 Vm^(-1)`