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The mass of a specimen of a ferromagneti...

The mass of a specimen of a ferromagnetic material is 0.6 kg. and its density is `7.8 xx 10^(3) kg//m3`. If the area of hysteresis loop of alternating magnetising field of frequency 50Hz is 0.722 MKS units then the hysteresis loss per second will be

A

`27.77 xx 10^(-5)`J

B

`2.777 xx 10^(-5) J`

C

`27.77 xx 10^(-4) J`

D

`27.77 xx 10^(-6) J`

Text Solution

Verified by Experts

The correct Answer is:
C
If V= volume of the material =mass / density ,
Area = area of hysteresis loop ,
v= frequency of alternate magnetic field applied and t= time for which field is applied then , energy loss in the material in t second is
`E=VA " "vt=((m)/(d))A " "bvt`
`=(0.6)/(7.8 xx 10^(3)) xx 0.722 xx 50 xx 1 =2.77 xx 20^(3) =27.7 xx 10^(-4)J`
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