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A metal surface of work function 1.07 eV...

A metal surface of work function `1.07 eV` is irradiated with light of wavelength `332 nm`. The retarding potential required to stop the escape of photo - electrons is

A

1.07 eV

B

2.68 eV

C

3.7 eV

D

4.81 eV

Text Solution

Verified by Experts

The correct Answer is:
B
Retarding potential,
`V_(8)=(hc)/(lamdae)-(phi_(0))/(e)=(1240xx10^(-9))/(330xx10^(-9))-1.07`
`=3.75-1.07`
`=2.68V`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-ELECTRONS AND PROTONS-Exercise 1
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  3. A metal surface of work function 1.07 eV is irradiated with light of w...

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  4. represents a graph of most energetic photoelectrons K(max)(in eV) and ...

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  5. Find the difference of kinetic energies of photoelectrons emitted from...

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  6. When ultraviolet light of wavelength 100 nm is incident upon silver pl...

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  7. Light of wavelength lamda strikes a photoelectric surface and electron...

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  8. The energy of a photon corresponding to the visible light of maximum w...

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  9. When a centimeter thick surface is illuminated with light of wavelengt...

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  10. The work function for Al, K and is 4.28 eV, 2.30 eV and 5.65 eV respec...

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  11. When photons of energy hv fall on an aluminium plate (of work function...

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  12. A photocell with a constannt potential differnce of V voolt across it,...

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  14. In a photoemissive cell, with exciting wavelength lambda, the faster e...

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  15. The threshold frequency of the metal of the cathode in a photoelectric...

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  16. Calculate the energy of a photon with momentum 3.3xx10^(-13)kg-ms^(-1)...

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  17. The energy that should be added to an electron, to reduce its de-Brogl...

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  19. A particle of mass 1 mg has the same wavelength as an electron moving ...

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  20. Monochromatic light of frequency 6.0 xx 10^(14) Hz is produced by a la...

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