When a cathode ray tube is operated at 2912 V, the velocity of electrons is `3.2xx10^(7)ms^(-1)`. Find the velocity of cathode ray if the tube is operated at 5824V.

Options

A. `2.4xx10^(7)ms^(-1)`
B. `5.2xx10^(7)ms^(-1)`
C. `4.525xx10^(7)ms^(-1)`
D. `2.4xx10^(6)ms^(-1)`

Answer

C

Explanation

`v=sqrt((2eV)/(m))`
Since, e and m are constant, `(v_(1))/(v_(2))=sqrt((V_(1))/(V_(2)))`
or `v_(2)=v_(1)sqrt((V_(1))/(V_(2)))=3.2xx10^(7)sqrt((5824)/(2912))=4.525xx10^(7)ms^(-1)`