If the frequency of light in a photoelectric experiment is doubled the stopping potential will

Options

A. be doubled
B. halved
C. become more than double
D. become less than double

Answer

C

Explanation

`eV_(0)=hf-phi_(0),V_(0)=`stopping potential, f=frequency
When frequency is doubled.
`eV_(0)'=2hf-phi_(0)=2(eV_(0)+phi_(0))-phi_(0)=2eV_(0)+phi_(0)`
`therefore" "V_(0)'=2V_(0)+phi_(0)//e`
so, stopping potential is more than double.