The de-Broglie wavelength `lamda`

Options

A. is proportional to mass
B. is proportional to impulse
C. is inversely proportional to impulse
D. does not depend on impulse

Answer

C

Explanation

de-Broglie wavelength `(lamda)` of a particle is related to its momentum (p) as, `lamda=(h)/(p)`
where h is planck's constant.
or `lamda=(h)/(mv)" "[becausep=mv]`
or `lamda=(h)/(m(v)/(t)*t)=(h)/(ma*t)=(h)/(F*t)" "[because F=ma]`
`implies lamda` is inversely proportional to impulse (F).