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The wavelength lamda(e) of ann electron ...

The wavelength `lamda_(e)` of ann electron and `lamda_(p)` of a photon of same energy E are related by

A

`lamda_(p) prop lamda_(e)^(2)`

B

`lamda_(p) prop lamda_(e)`

C

`lamda_(p) prop sqrt(lamda_(e))`

D

`lamda_(p) prop (1)/(sqrt(lamda_(e)))`

Text Solution

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The correct Answer is:
A

Wavelength of electron,
`lamda_(e)=(h)/(sqrt(2mE)) and ` proton, `lamda_(p)=(hc)/(E)`
`implies lamda_(e)^(2)=(h^(2))/(2mE) or E=(hc)/(lamda_(p))`
`therefore lamda_(e)^(2)=(h^(2))/(2m*(hc)/(lamda_(p))) implies lamda_(e)^(2)=(h^(2))/(2mhc)lamda_(p) implies lamda_(e)^(2)proplamda_(p)`
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