The dimensions of Planck's constant is the same as the product of

Options

A. force and time
B. force, displacement and time
C. force and distance
D. time and displacement

Answer

B

Explanation

The dimensions of planck's constant, ltbr. `[h]=[(E)/(v)] =[ML^(2)T^(-1)]`
force, `[F]=[MLT^(-2)]`
Displacement, `[d]=[L]`
Time `[t]=[T]`
`therefore [F][d][t]=[MLT^(-2)][L][T]=[ML^(2)T^(-1)]`
Hence, the dimensions of planck's constant is the same as the product of force, displacement and time.