In given circuit, current gain of transistor is `beta=100`, the output of amplifier will be

Options

A. 10 V
B. 0.1 V
C. 1.0 V
D. 100 V

Answer

A

Explanation

`I_("in")=(V)/(R_("in"))=(1xx10^(-3))/(1xx10^(3))=10^(-6)A`
`I_("out")=betaI_("in")=100xx10^(-6)A=10^(-4)A`
`V_("out")=I_("out")xxR_(L)=10^(-4)xx100xx10^(3)=10V`