In an unbiased p-n junction,

Options

A. potential at p is more than that at n
B. potential at p is less than that at n
C. potential at p is equal to that at n
D. potential at p is positive and that at n is negative

Explanation

To solve the question regarding the potential difference in an unbiased p-n junction, we will analyze the characteristics of the p-n junction and the behavior of charge carriers.

### Step-by-Step Solution:

1. **Understanding the p-n Junction**:
- A p-n junction is formed by joining p-type and n-type semiconductors. The p-type semiconductor has an abundance of holes (positive charge carriers), while the n-type semiconductor has an abundance of electrons (negative charge carriers).

2. **Behavior of Charge Carriers**:
- In an unbiased p-n junction (meaning no external voltage is applied), the majority carriers in the p-type (holes) and n-type (electrons) will not move significantly across the junction. However, minority carriers (electrons in p-type and holes in n-type) will diffuse across the junction.

3. **Formation of Depletion Region**:
- As the minority carriers diffuse, they recombine with majority carriers, leading to a region near the junction that is depleted of charge carriers. This creates an electric field across the junction.

4. **Potential Difference**:
- The electric field established by the separation of charges results in a built-in potential difference across the junction. In this case, the p-side (where holes are majority carriers) will have a higher potential compared to the n-side (where electrons are majority carriers).

5. **Conclusion**:
- Therefore, in an unbiased p-n junction, the potential at the p-side is greater than that at the n-side. This means that the potential at p is more than that at n.

6. **Answering the Question**:
- Based on the analysis, the correct option is that the potential at p is greater than that at n.

### Final Answer:
The potential at p is more than that at n.