If `beta, R_(L)` and r are the AC current gain, load resistance and the input resistance of a transistor respectively in CE configuration, the voltage and the power gains respectively are

Options

A. `beta(R_(L))/(r) and beta^(2)(R_(L))/(r)`
B. `beta(r)/(R_(L)) and beta^(2)(r)/(R_(L))`
C. `beta (R_(L))/(r) and beta((R_(L))/(r))^(2)`
D. `beta(r)/(R_(L)) and beta((r)/(R_(L)))^(2)`

Answer

A

Explanation

Transistor as CE amplifier
Voltage gain, `A_(V)=(DeltaV_(0))/(DeltaV_(i))=beta_(AC)xx"Resistance gain"=betaxx(R_(L))/(r )`
Power gain `=(DeltaP_(0))/(DeltaP_(i))=beta_(AC)^(2)xx"Resistance gain"=beta^(2)xx(R_(L))/(r )`