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The current of transistor in common emit...

The current of transistor in common emitter mode is 49. The change in collector current and emitter current corresponding to the change in the base current by `5.0 muA`m will be :-

A

`245mu A, 250mu A`

B

`240mu A, 235mu A`

C

`260mu A, 255mu A`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A

Current gain, `beta=(DeltaI_(C))/(DeltaI_(B))`, where `DeltaI_(C )` is change in collector current and `DeltaI_(B)` is change in base current.
`rArr DeltaI_(C)=betaDeltaI_(B)=49xx5=245 muA`
Also, `DeltaI_(E)=DeltaI_(B)+DeltaI_(C)`
`=(245+5)muA=250muA`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-SEMICONDUCTORS-Exercise 1 ( TOPICAL PROBLEMS )
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