The current I through `10Omega` resistor in the circuit given below is

Options

A. 50 mA
B. 20 mA
C. 40 mA
D. 80 mA

Answer

D

Explanation

Here, diode `D_(2)` is reverse biased while `D_(1)` is forward biase (d) So, no current flows across `D_(2)`, current flows through diode `D_(1)`.
`I=(V)/(R )=(2)/(10+15)=(2)/(25)=0.08A=80mA`