In a common base amplifier circuit, calculate the change in base current if that in the emitter current is `2mA` and `alpha=0.98`

Options

A. 0.04 mA
B. 196 mA
C. 0.98 mA
D. 2 mA

Answer

A

Explanation

As, `Delta i_(c)=alpha Delta i_(e) rArr 0.98 xx 2 =1.96`
`therefore Delta i_(b)=Delta i_(e)-Delta i_(c)=2-1.96=0.04 mA`