In a common emitter amplifier, using output reisistance of `5000` ohm and input resistance fo `2000`ohm, if the peak value of input signal voltage is `10 m V` and `beta=50`, then the peak value of output voltage is

Options

A. `5xx10^(-6)V`
B. `12.50 xx 10^(-6)V`
C. 1.25 V
D. 125.0 V

Answer

C

Explanation

`A_(v)=(Delta V_(0))/(DeltaV_(i))=beta(R_(0))/(R_(i)) and DeltaV_(0)=DeltaV_(i)xxbeta(R_(0))/(R_(i))`
`therefore DeltaV_(0)= 10xx50 xx(500)/(2000)`
`DeltaV_(0)=1250mV=1.25V`