The circuit has two oppositively connected ideal diodes in parallel what is the current flowing in the circuit ?

Options

A. 1.71 A
B. 2.00 A
C. 2.31 A
D. 133 A

Answer

B

Explanation

In the given circuit diode `D_(1)` is reverse biased while `D_(2)` is forward biased, so the circuit can be redrawn as

`because ` For ideal diodes, reverse biased means open and forward biased means short
Apply KVL to get current flowing through the circuit.
`-12+4i+2i =0`
`rArr i=(12)/(6)=2A`