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In a triode, gm=2xx10^(-3)ohm^(-1) , mu=...

In a triode, `gm=2xx10^(-3)ohm^(-1) , mu=42`, resistance load, R = 50 kilo ohm. The voltage amplification obtained from this triode will be

A

30.42

B

29.57

C

28.18

D

27.15

Text Solution

Verified by Experts

The correct Answer is:
B
As, `A_(v)=(muR)/(r_(p)+R)=(muR)/((mu//g_(m))+R)`
`=(42xx(50xx10^(3)))/(42//(2xx10^(-3))+50xx10^(3))=29.57`
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