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In common base circuit of a transistor ,...

In common base circuit of a transistor , current amplification factor is `0.95`. Calculate the emitter current , if base current is `0.2` mA

A

2 mA

B

4 mA

C

6 mA

D

8 mA

Text Solution

Verified by Experts

The correct Answer is:
B
Given, `alpha=0.95, I_(b)=0.2mA`
As `alpha=(I_(c))/(I_(e))=(I_(e)-I_(b))/(I_(e))=1-(I_(b))/(I_(e))`
`rArr (I_(b))/(I_(e))=1-alpha=1-0.95 =0.05`
`(0.2)/(0.05)mA=I_(e) rArr I_(e)=4mA`
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