The depletion layer in diode is `1 mum` wide and the knee potential is `0.6 V`, then the electric field in the depletion layer will be

Options

A. `5xx10^(6)Vm^(-1)`
B. `5xx10^(-7)Vm^(-1)`
C. `5xx10^(5)Vm^(-1)`
D. `5xx10^(-1)Vm^(-1)`

Answer

C

Explanation

In forward biasing condition, the linner electric field is given by `E=(DeltaV)/(Deltar)`
`or |E|=(DeltaV)/(Deltar)=(5xx10^(-1))/(10^(-6))`
`=5xx10^(5) Vm^(-1)`